 Thursday, November 15, 2018

Guest Post: Implementing a Calculator REPL in RPython

This is a tutorial style post that walks through using the RPython translation toolchain to create a REPL that executes basic math expressions.

We will do that by scanning the user's input into tokens, compiling those tokens into bytecode and running that bytecode in our own virtual machine. Don't worry if that sounds horribly complicated, we are going to explain it step by step.

This post is a bit of a diversion while on my journey to create a compliant lox implementation using the RPython translation toolchain. The majority of this work is a direct RPython translation of the low level C guide from Bob Nystrom (@munificentbob) in the excellent book craftinginterpreters.com specifically the chapters 14 – 17.

As this post is rather long I'll break it into a few major sections. In each section we will have something that translates with RPython, and at the end it all comes together.

A REPL

So if you're a Python programmer you might be thinking this is pretty trivial right?

I mean if we ignore input errors, injection attacks etc couldn't we just do something like this:

"""
A pure python REPL that can parse simple math expressions
"""
while True:
print(eval(raw_input("> ")))

Well it does appear to do the trick:

\$ python2 section-1-repl/main.py
> 3 + 4 * ((1.0/(2 * 3 * 4)) + (1.0/(4 * 5 * 6)) - (1.0/(6 * 7 * 8)))
3.1880952381

So can we just ask RPython to translate this into a binary that runs magically faster?

Let's see what happens. We need to add two functions for RPython to get its bearings (entry_point and target) and call the file targetXXX:

targetrepl1.py

def repl():
while True:
print eval(raw_input('> '))

def entry_point(argv):
repl()
return 0

def target(driver, *args):
return entry_point, None

Which at translation time gives us this admonishment that accurately tells us we are trying to call a Python built-in raw_input that is unfortunately not valid RPython.

\$ rpython ./section-1-repl/targetrepl1.py
...SNIP...
[translation:ERROR] AnnotatorError:

object with a __call__ is not RPython: <built-in function raw_input>
Processing block:
block@18 is a <class 'rpython.flowspace.flowcontext.SpamBlock'>
in (target1:2)repl
containing the following operations:
v0 = simple_call((builtin_function raw_input), ('> '))
v1 = simple_call((builtin_function eval), v0)
v2 = str(v1)
v3 = simple_call((function rpython_print_item), v2)
v4 = simple_call((function rpython_print_newline))

Ok so we can't use raw_input or eval but that doesn't faze us. Let's get the input from a stdin stream and just print it out (no evaluation).

targetrepl2.py

from rpython.rlib import rfile

LINE_BUFFER_LENGTH = 1024

def repl(stdin):
while True:
print "> ",
print line

def entry_point(argv):
stdin, stdout, stderr = rfile.create_stdio()
try:
repl(stdin)
except:
return 0

def target(driver, *args):
return entry_point, None

Translate targetrepl2.py – we can add an optimization level if we are so inclined:

\$ rpython --opt=2 section-1-repl/targetrepl2.py
...SNIP...
[Timer] Timings:
[Timer] annotate                       ---  1.2 s
[Timer] rtype_lltype                   ---  0.9 s
[Timer] backendopt_lltype              ---  0.6 s
[Timer] stackcheckinsertion_lltype     ---  0.0 s
[Timer] database_c                     --- 15.0 s
[Timer] source_c                       ---  1.6 s
[Timer] compile_c                      ---  1.9 s
[Timer] =========================================
[Timer] Total:                         --- 21.2 s

No errors!? Let's try it out:

\$ ./target2-c
1 + 2
>  1 + 2

^C

Ahh our first success – let's quickly deal with the flushing fail by using the stdout stream directly as well. Let's print out the input in quotes:

from rpython.rlib import rfile

LINE_BUFFER_LENGTH = 1024

def repl(stdin, stdout):
while True:
stdout.write("> ")
print '"%s"' % line.strip()

def entry_point(argv):
stdin, stdout, stderr = rfile.create_stdio()
try:
repl(stdin, stdout)
except:
pass
return 0

def target(driver, *args):
return entry_point, None

Translation works, and the test run too:

\$ ./target3-c
> hello this seems better
"hello this seems better"
> ^C

So we are in a good place with taking user input and printing output... What about the whole math evaluation thing we were promised? For that we are can probably leave our RPython REPL behind for a while and connect it up at the end.

A virtual machine

A virtual machine is the execution engine of our basic math interpreter. It will be very simple, only able to do simple tasks like addition. I won't go into any depth to describe why we want a virtual machine, but it is worth noting that many languages including Java and Python make this decision to compile to an intermediate bytecode representation and then execute that with a virtual machine. Alternatives are compiling directly to native machine code like (earlier versions of) the V8 JavaScript engine, or at the other end of the spectrum executing an abstract syntax tree – which is what the Truffle approach to building VMs is based on.

We are going to keep things very simple. We will have a stack where we can push and pop values, we will only support floats, and our VM will only implement a few very basic operations.

OpCodes

In fact our entire instruction set is:

OP_CONSTANT
OP_RETURN
OP_NEGATE
OP_SUBTRACT
OP_MULTIPLY
OP_DIVIDE

Since we are targeting RPython we can't use the nice enum module from the Python standard library, so instead we just define a simple class with class attributes.

We should start to get organized, so we will create a new file opcodes.py and add this:

class OpCode:
OP_CONSTANT = 0
OP_RETURN = 1
OP_NEGATE = 2
OP_SUBTRACT = 4
OP_MULTIPLY = 5
OP_DIVIDE = 6

Chunks

To start with we need to get some infrastructure in place before we write the VM engine.

Following craftinginterpreters.com we start with a Chunk object which will represent our bytecode. In RPython we have access to Python-esq lists so our code object will just be a list of OpCode values – which are just integers. A list of ints, couldn't get much simpler.

section-2-vm/chunk.py

class Chunk:
code = None

def __init__(self):
self.code = []

def write_chunk(self, byte):
self.code.append(byte)

def disassemble(self, name):
print "== %s ==\n" % name
i = 0
while i < len(self.code):
i = disassemble_instruction(self, i)

From here on I'll only present minimal snippets of code instead of the whole lot, but I'll link to the repository with the complete example code. For example the various debugging including disassemble_instruction isn't particularly interesting to include verbatim. See the github repo for full details

We need to check that we can create a chunk and disassemble it. The quickest way to do this is to use Python during development and debugging then every so often try to translate it.

Getting the disassemble part through the RPython translator was a hurdle for me as I quickly found that many str methods such as format are not supported, and only very basic % based formatting is supported. I ended up creating helper functions for string manipulation such as:

def leftpad_string(string, width, char=" "):
l = len(string)
if l > width:
return string
return char * (width - l) + string

Let's write a new entry_point that creates and disassembles a chunk of bytecode. We can set the target output name to vm1 at the same time:

targetvm1.py

def entry_point(argv):
bytecode = Chunk()
bytecode.write_chunk(OpCode.OP_RETURN)
bytecode.disassemble("hello world")
return 0

def target(driver, *args):
driver.exe_name = "vm1"
return entry_point, None

Running this isn't going to be terribly interesting, but it is always nice to know that it is doing what you expect:

\$ ./vm1
== hello world ==

0001 OP_RETURN

Chunks of data

Ref: http://www.craftinginterpreters.com/chunks-of-bytecode.html#constants

So our bytecode is missing a very crucial element – the values to operate on!

As with the bytecode we can store these constant values as part of the chunk directly in a list. Each chunk will therefore have a constant data component, and a code component.

Edit the chunk.py file and add the new instance attribute constants as an empty list, and a new method add_constant.

self.constants.append(value)
return len(self.constants) - 1

Now to use this new capability we can modify our example chunk to write in some constants before the OP_ADD:

bytecode = Chunk()
bytecode.write_chunk(OpCode.OP_CONSTANT)
bytecode.write_chunk(constant)

bytecode.write_chunk(OpCode.OP_CONSTANT)
bytecode.write_chunk(constant)

bytecode.write_chunk(OpCode.OP_RETURN)

Which still translates with RPython and when run gives us the following disassembled bytecode:

== adding constants ==

0000 OP_CONSTANT  (00)        '1'
0002 OP_CONSTANT  (01)        '2'
0005 OP_RETURN

We won't go down the route of serializing the bytecode to disk, but this bytecode chunk (including the constant data) could be saved and executed on our VM later – like a Java .class file. Instead we will pass the bytecode directly to our VM after we've created it during the compilation process.

Emulation

So those four instructions of bytecode combined with the constant value mapping 00 -> 1.0 and 01 -> 2.0 describes individual steps for our virtual machine to execute. One major point in favor of defining our own bytecode is we can design it to be really simple to execute – this makes the VM really easy to implement.

As I mentioned earlier this virtual machine will have a stack, so let's begin with that. Now the stack is going to be a busy little beast – as our VM takes instructions like OP_ADD it will pop off the top two values from the stack, and push the result of adding them together back onto the stack. Although dynamically resizing Python lists are marvelous, they can be a little slow. RPython can take advantage of a constant sized list which doesn't make our code much more complicated.

To do this we will define a constant sized list and track the stack_top directly. Note how we can give the RPython translator hints by adding assertions about the state that the stack_top will be in.

class VM(object):
STACK_MAX_SIZE = 256
stack = None
stack_top = 0

def __init__(self):
self._reset_stack()

def _reset_stack(self):
self.stack =  * self.STACK_MAX_SIZE
self.stack_top = 0

def _stack_push(self, value):
assert self.stack_top < self.STACK_MAX_SIZE
self.stack[self.stack_top] = value
self.stack_top += 1

def _stack_pop(self):
assert self.stack_top >= 0
self.stack_top -= 1
return self.stack[self.stack_top]

def _print_stack(self):
print "         ",
if self.stack_top <= 0:
print "[]",
else:
for i in range(self.stack_top):
print "[ %s ]" % self.stack[i],
print

Now we get to the main event, the hot loop, the VM engine. Hope I haven't built it up to much, it is actually really simple! We loop until the instructions tell us to stop (OP_RETURN), and dispatch to other simple methods based on the instruction.

def _run(self):
while True:

if instruction == OpCode.OP_RETURN:
print "%s" % self._stack_pop()
return InterpretResultCode.INTERPRET_OK
elif instruction == OpCode.OP_CONSTANT:
self._stack_push(constant)
elif instruction == OpCode.OP_ADD:

Now the _read_byte method will have to keep track of which instruction we are up to. So add an instruction pointer (ip) to the VM with an initial value of 0. Then _read_byte is simply getting the next bytecode (int) from the chunk's code:

instruction = self.chunk.code[self.ip]
self.ip += 1
return instruction

If the instruction is OP_CONSTANT we take the constant's address from the next byte of the chunk's code, retrieve that constant value and add it to the VM's stack.

return self.chunk.constants[constant_index]

Finally our first arithmetic operation OP_ADD, what it has to achieve doesn't require much explanation: pop two values from the stack, add them together, push the result. But since a few operations all have the same template we introduce a layer of indirection – or abstraction – by introducing a reusable _binary_op helper method.

@specialize.arg(1)
def _binary_op(self, operator):
op2 = self._stack_pop()
op1 = self._stack_pop()
result = operator(op1, op2)
self._stack_push(result)

@staticmethod
return op1 + op2

Note we tell RPython to specialize _binary_op on the first argument. This causes RPython to make a copy of _binary_op for every value of the first argument passed, which means that each copy contains a call to a particular operator, which can then be inlined.

To be able to run our bytecode the only thing left to do is to pass in the chunk and call _run():

def interpret_chunk(self, chunk):
if self.debug_trace:
print "== VM TRACE =="
self.chunk = chunk
self.ip = 0
try:
result = self._run()
return result
except:
return InterpretResultCode.INTERPRET_RUNTIME_ERROR

targetvm3.py connects the pieces:

def entry_point(argv):
bytecode = Chunk()
bytecode.write_chunk(OpCode.OP_CONSTANT)
bytecode.write_chunk(constant)
bytecode.write_chunk(OpCode.OP_CONSTANT)
bytecode.write_chunk(constant)
bytecode.write_chunk(OpCode.OP_RETURN)

vm = VM()
vm.interpret_chunk(bytecode)

return 0

I've added some trace debugging so we can see what the VM and stack is doing.

The whole thing translates with RPython, and when run gives us:

./vm3
== VM TRACE ==
[]
0000 OP_CONSTANT  (00)        '1'
[ 1 ]
0002 OP_CONSTANT  (01)        '2'
[ 1 ] [ 2 ]
[ 3 ]
0005 OP_RETURN
3

Yes we just computed the result of 1+2. Pat yourself on the back.

At this point it is probably valid to check that the translated executable is actually faster than running our program directly in Python. For this trivial example under Python2/pypy this targetvm3.py file runs in the 20ms – 90ms region, and the compiled vm3 runs in <5ms. Something useful must be happening during the translation.

I won't go through the code adding support for our other instructions as they are very similar and straightforward. Our VM is ready to execute our chunks of bytecode, but we haven't yet worked out how to take the entered expression and turn that into this simple bytecode. This is broken into two steps, scanning and compiling.

Scanning the source

All the source for this section can be found in section-3-scanning.

The job of the scanner is to take the raw expression string and transform it into a sequence of tokens. This scanning step will strip out whitespace and comments, catch errors with invalid token and tokenize the string. For example the input "( 1 + 2 ) would get tokenized into LEFT_PAREN, NUMBER(1), PLUS, NUMBER(2), RIGHT_PAREN.

As with our OpCodes we will just define a simple Python class to define an int for each type of token:

class TokenTypes:
ERROR = 0
EOF = 1
LEFT_PAREN = 2
RIGHT_PAREN = 3
MINUS = 4
PLUS = 5
SLASH = 6
STAR = 7
NUMBER = 8

A token has to keep some other information as well – keeping track of the location and length of the token will be helpful for error reporting. The NUMBER token clearly needs some data about the value it is representing: we could include a copy of the source lexeme (e.g. the string 2.0), or parse the value and store that, or – what we will do in this blog – use the location and length information as pointers into the original source string. Every token type (except perhaps ERROR) will use this simple data structure:

class Token(object):

def __init__(self, start, length, token_type):
self.start = start
self.length = length
self.type = token_type

Our soon to be created scanner will create these Token objects which refer back to addresses in some source. If the scanner sees the source "( 1 + 2.0 )" it would emit the following tokens:

Token(0, 1, TokenTypes.LEFT_PAREN)
Token(2, 1, TokenTypes.NUMBER)
Token(4, 1, TokenTypes.PLUS)
Token(6, 3, TokenTypes.NUMBER)
Token(10, 1, TokenTypes.RIGHT_PAREN)

Scanner

Let's walk through the scanner implementation method by method. The scanner will take the source and pass through it once, creating tokens as it goes.

class Scanner(object):

def __init__(self, source):
self.source = source
self.start = 0
self.current = 0

The start and current variables are character indices in the source string that point to the current substring being considered as a token.

For example in the string "(51.05+2)" while we are tokenizing the number 51.05 we will have start pointing at the 5, and advance current character by character until the character is no longer part of a number. Midway through scanning the number the start and current values might point to 1 and 4 respectively:

0 1 2 3 4 5 6 7 8
"(" "5" "1" "." "0" "5" "+" "2" ")"
^  ^

From current=4 the scanner peeks ahead and sees that the next character (5) is a digit, so will continue to advance.

0 1 2 3 4 5 6 7 8
"(" "5" "1" "." "0" "5" "+" "2" ")"
^  ^

When the scanner peeks ahead and sees the "+" it will create the number token and emit it. The method that carry's out this tokenizing is _number:

def _number(self):
while self._peek().isdigit():

# Look for decimal point
if self._peek() == '.' and self._peek_next().isdigit():
while self._peek().isdigit():

return self._make_token(TokenTypes.NUMBER)

It relies on a few helpers to look ahead at the upcoming characters:

def _peek(self):
if self._is_at_end():
return '\0'
return self.source[self.current]

def _peek_next(self):
if self._is_at_end():
return '\0'
return self.source[self.current+1]

def _is_at_end(self):
return len(self.source) == self.current

If the character at current is still part of the number we want to call advance to move on by one character.

self.current += 1
return self.source[self.current - 1]

Once the isdigit() check fails in _number() we call _make_token() to emit the token with the NUMBER type.

def _make_token(self, token_type):
start=self.start,
length=(self.current - self.start),
token_type=token_type
)

Note again that the token is linked to an index address in the source, rather than including the string value.

Our scanner is pull based, a token will be requested via scan_token. First we skip past whitespace and depending on the characters emit the correct token:

def scan_token(self):
# skip any whitespace
while True:
char = self._peek()
if char in ' \r\t\n':
break

self.start = self.current

if self._is_at_end():
return self._make_token(TokenTypes.EOF)

if char.isdigit():
return self._number()

if char == '(':
return self._make_token(TokenTypes.LEFT_PAREN)
if char == ')':
return self._make_token(TokenTypes.RIGHT_PAREN)
if char == '-':
return self._make_token(TokenTypes.MINUS)
if char == '+':
return self._make_token(TokenTypes.PLUS)
if char == '/':
return self._make_token(TokenTypes.SLASH)
if char == '*':
return self._make_token(TokenTypes.STAR)

return ErrorToken("Unexpected character", self.current)

If this was a real programming language we were scanning, this would be the point where we add support for different types of literals and any language identifiers/reserved words.

At some point we will need to parse the literal value for our numbers, but we leave that job for some later component, for now we'll just add a get_token_string helper. To make sure that RPython is happy to index arbitrary slices of source we add range assertions:

def get_token_string(self, token):
if isinstance(token, ErrorToken):
else:
end_loc = token.start + token.length
assert end_loc < len(self.source)
assert end_loc > 0
return self.source[token.start:end_loc]

A simple entry point can be used to test our scanner with a hard coded source string:

targetscanner1.py

from scanner import Scanner, TokenTypes, TokenTypeToName

def entry_point(argv):

source = "(   1   + 2.0 )"

scanner = Scanner(source)
t = scanner.scan_token()
while t.type != TokenTypes.EOF and t.type != TokenTypes.ERROR:
print TokenTypeToName[t.type],
if t.type == TokenTypes.NUMBER:
print "(%s)" % scanner.get_token_string(t),
print
t = scanner.scan_token()
return 0

RPython didn't complain, and lo it works:

\$ ./scanner1
LEFT_PAREN
NUMBER (1)
PLUS
NUMBER (2.0)
RIGHT_PAREN

Let's connect our REPL to the scanner.

targetscanner2.py

from rpython.rlib import rfile
from scanner import Scanner, TokenTypes, TokenTypeToName

LINE_BUFFER_LENGTH = 1024

def repl(stdin, stdout):
while True:
stdout.write("> ")

scanner = Scanner(source)
t = scanner.scan_token()
while t.type != TokenTypes.EOF and t.type != TokenTypes.ERROR:
print TokenTypeToName[t.type],
if t.type == TokenTypes.NUMBER:
print "(%s)" % scanner.get_token_string(t),
print
t = scanner.scan_token()

def entry_point(argv):
stdin, stdout, stderr = rfile.create_stdio()
try:
repl(stdin, stdout)
except:
pass
return 0

With our REPL hooked up we can now scan tokens from arbitrary input:

\$ ./scanner2
> (3 *4) - -3
LEFT_PAREN
NUMBER (3)
STAR
NUMBER (4)
RIGHT_PAREN
MINUS
MINUS
NUMBER (3)
> ^C

Compiling expressions

• https://www.craftinginterpreters.com/compiling-expressions.html
• http://effbot.org/zone/simple-top-down-parsing.htm

The final piece is to turn this sequence of tokens into our low level bytecode instructions for the virtual machine to execute. Buckle up, we are about to write us a compiler.

Our compiler will take a single pass over the tokens using Vaughan Pratt’s parsing technique, and output a chunk of bytecode – if we do it right it will be compatible with our existing virtual machine.

Remember the bytecode we defined above is really simple – by relying on our stack we can transform a nested expression into a sequence of our bytecode operations.

To make this more concrete let's go through by hand translating an expression into bytecode.

Our source expression:

(3 + 2) - (7 * 2)

If we were to make an abstract syntax tree we'd get something like this: Now if we start at the first sub expression (3+2) we can clearly note from the first open bracket that we must see a close bracket, and that the expression inside that bracket must be valid on its own. Not only that but regardless of the inside we know that the whole expression still has to be valid. Let's focus on this first bracketed expression, let our attention recurse into it so to speak.

This gives us a much easier problem – we just want to get our virtual machine to compute 3 + 2. In this bytecode dialect we would load the two constants, and then add them with OP_ADD like so:

OP_CONSTANT  (00) '3.000000'
OP_CONSTANT  (01) '2.000000'

The effect of our vm executing these three instructions is that sitting pretty at the top of the stack is the result of the addition. Winning.

Jumping back out from our bracketed expression, our next token is MINUS, at this point we have a fair idea that it must be used in an infix position. In fact whatever token followed the bracketed expression it must be a valid infix operator, if not the expression is over or had a syntax error.

Assuming the best from our user (naive), we handle MINUS the same way we handled the first PLUS. We've already got the first operand on the stack, now we compile the right operand and then write out the bytecode for OP_SUBTRACT.

The right operand is another simple three instructions:

OP_CONSTANT  (02) '7.000000'
OP_CONSTANT  (03) '2.000000'
OP_MULTIPLY

Then we finish our top level binary expression and write a OP_RETURN to return the value at the top of the stack as the execution's result. Our final hand compiled program is:

OP_CONSTANT  (00) '3.000000'
OP_CONSTANT  (01) '2.000000'
OP_CONSTANT  (02) '7.000000'
OP_CONSTANT  (03) '2.000000'
OP_MULTIPLY
OP_SUBTRACT
OP_RETURN

Ok that wasn't so hard was it? Let's try make our code do that.

We define a parser object which will keep track of where we are, and whether things have all gone horribly wrong:

class Parser(object):
def __init__(self):
self.panic_mode = False
self.current = None
self.previous = None

The compiler will also be a class, we'll need one of our Scanner instances to pull tokens from, and since the output is a bytecode Chunk let's go ahead and make one of those in our compiler initializer:

class Compiler(object):

def __init__(self, source):
self.parser = Parser()
self.scanner = Scanner(source)
self.chunk = Chunk()

Since we have this (empty) chunk of bytecode we will make a helper method to add individual bytes. Every instruction will pass from our compiler into an executable program through this simple .

def emit_byte(self, byte):
self.current_chunk().write_chunk(byte)

To quote from Bob Nystrom on the Pratt parsing technique:

the implementation is a deceptively-simple handful of deeply intertwined code

I don't actually think I can do justice to this section. Instead I suggest reading his treatment in Pratt Parsers: Expression Parsing Made Easy which explains the magic behind the parsing component. Our only major difference is instead of creating an AST we are going to directly emit bytecode for our VM.

Now that I've absolved myself from taking responsibility in explaining this somewhat tricky concept, I'll discuss some of the code from compiler.py, and walk through what happens for a particular rule.

I'll jump straight to the juicy bit the table of parse rules. We define a ParseRule for each token, and each rule comprises:

• an optional handler for when the token is as a prefix (e.g. the minus in (-2)),
• an optional handler for whet the token is used infix (e.g. the slash in 2/47)
• a precedence value (a number that determines what is of higher precedence)
rules = [
ParseRule(None,              None,            Precedence.NONE),   # ERROR
ParseRule(None,              None,            Precedence.NONE),   # EOF
ParseRule(Compiler.grouping, None,            Precedence.CALL),   # LEFT_PAREN
ParseRule(None,              None,            Precedence.NONE),   # RIGHT_PAREN
ParseRule(Compiler.unary,    Compiler.binary, Precedence.TERM),   # MINUS
ParseRule(None,              Compiler.binary, Precedence.TERM),   # PLUS
ParseRule(None,              Compiler.binary, Precedence.FACTOR), # SLASH
ParseRule(None,              Compiler.binary, Precedence.FACTOR), # STAR
ParseRule(Compiler.number,   None,            Precedence.NONE),   # NUMBER
]

These rules really are the magic of our compiler. When we get to a particular token such as MINUS we see if it is an infix operator and if so we've gone and got its first operand ready. At all times we rely on the relative precedence; consuming everything with higher precedence than the operator we are currently evaluating.

In the expression:

2 + 3 * 4

The * has higher precedence than the +, so 3 * 4 will be parsed together as the second operand to the first infix operator (the +) which follows the BEDMAS order of operations I was taught at high school.

To encode these precedence values we make another Python object moonlighting as an enum:

class Precedence(object):
NONE = 0
DEFAULT = 1
TERM = 2        # + -
FACTOR = 3      # * /
UNARY = 4       # ! - +
CALL = 5        # ()
PRIMARY = 6

What happens in our compiler when turning -2.0 into bytecode? Assume we've just pulled the token MINUS from the scanner. Every expression has to start with some type of prefix – whether that is:

• a bracket group (,
• a number 2,
• or a prefix unary operator -.

Knowing that, our compiler assumes there is a prefix handler in the rule table – in this case it points us at the unary handler.

def parse_precedence(self, precedence):
# parses any expression of a given precedence level or higher
prefix_rule = self._get_rule(self.parser.previous.type).prefix
prefix_rule(self)

unary is called:

def unary(self):
op_type = self.parser.previous.type
# Compile the operand
self.parse_precedence(Precedence.UNARY)
# Emit the operator instruction
if op_type == TokenTypes.MINUS:
self.emit_byte(OpCode.OP_NEGATE)

Here – before writing the OP_NEGATE opcode we recurse back into parse_precedence to ensure that whatever follows the MINUS token is compiled – provided it has higher precedence than unary – e.g. a bracketed group. Crucially at run time this recursive call will ensure that the result is left on top of our stack. Armed with this knowledge, the unary method just has to emit a single byte with the OP_NEGATE opcode.

Test compilation

Now we can test our compiler by outputting disassembled bytecode of our user entered expressions. Create a new entry_point targetcompiler:

from rpython.rlib import rfile
from compiler import Compiler

LINE_BUFFER_LENGTH = 1024

def entry_point(argv):
stdin, stdout, stderr = rfile.create_stdio()

try:
while True:
stdout.write("> ")
compiler = Compiler(source, debugging=True)
compiler.compile()
except:
pass
return 0

Translate it and test it out:

\$ ./compiler1
> (2/4 + 1/2)
== code ==

0000 OP_CONSTANT  (00) '2.000000'
0002 OP_CONSTANT  (01) '4.000000'
0004 OP_DIVIDE
0005 OP_CONSTANT  (02) '1.000000'
0007 OP_CONSTANT  (00) '2.000000'
0009 OP_DIVIDE
0011 OP_RETURN

Now if you've made it this far you'll be eager to finally connect everything together by executing this bytecode with the virtual machine.

End to end

All the pieces slot together rather easily at this point, create a new file targetcalc.py and define our entry point:

from rpython.rlib import rfile
from compiler import Compiler
from vm import VM

LINE_BUFFER_LENGTH = 4096

def entry_point(argv):
stdin, stdout, stderr = rfile.create_stdio()
vm = VM()
try:
while True:
stdout.write("> ")
if source:
compiler = Compiler(source, debugging=False)
compiler.compile()
vm.interpret_chunk(compiler.chunk)
except:
pass
return 0

def target(driver, *args):
driver.exe_name = "calc"
return entry_point, None

Let's try catch it out with a double negative:

\$ ./calc
> 2--3
== VM TRACE ==
[]
0000 OP_CONSTANT  (00) '2.000000'
[ 2.000000 ]
0002 OP_CONSTANT  (01) '3.000000'
[ 2.000000 ] [ 3.000000 ]
0004 OP_NEGATE
[ 2.000000 ] [ -3.000000 ]
0005 OP_SUBTRACT
[ 5.000000 ]
0006 OP_RETURN
5.000000

Ok well let's evaluate the first 50 terms of the Nilakantha Series:

\$ ./calc
> 3 + 4 * ((1/(2 * 3 * 4)) + (1/(4 * 5 * 6)) - (1/(6 * 7 * 8)) + (1/(8 * 9 * 10)) - (1/(10 * 11 * 12)) + (1/(12 * 13 * 14)) - (1/(14 * 15 * 16)) + (1/(16 * 17 * 18)) - (1/(18 * 19 * 20)) + (1/(20 * 21 * 22)) - (1/(22 * 23 * 24)) + (1/(24 * 25 * 26)) - (1/(26 * 27 * 28)) + (1/(28 * 29 * 30)) - (1/(30 * 31 * 32)) + (1/(32 * 33 * 34)) - (1/(34 * 35 * 36)) + (1/(36 * 37 * 38)) - (1/(38 * 39 * 40)) + (1/(40 * 41 * 42)) - (1/(42 * 43 * 44)) + (1/(44 * 45 * 46)) - (1/(46 * 47 * 48)) + (1/(48 * 49 * 50)) - (1/(50 * 51 * 52)) + (1/(52 * 53 * 54)) - (1/(54 * 55 * 56)) + (1/(56 * 57 * 58)) - (1/(58 * 59 * 60)) + (1/(60 * 61 * 62)) - (1/(62 * 63 * 64)) + (1/(64 * 65 * 66)) - (1/(66 * 67 * 68)) + (1/(68 * 69 * 70)) - (1/(70 * 71 * 72)) + (1/(72 * 73 * 74)) - (1/(74 * 75 * 76)) + (1/(76 * 77 * 78)) - (1/(78 * 79 * 80)) + (1/(80 * 81 * 82)) - (1/(82 * 83 * 84)) + (1/(84 * 85 * 86)) - (1/(86 * 87 * 88)) + (1/(88 * 89 * 90)) - (1/(90 * 91 * 92)) + (1/(92 * 93 * 94)) - (1/(94 * 95 * 96)) + (1/(96 * 97 * 98)) - (1/(98 * 99 * 100)) + (1/(100 * 101 * 102)))

== VM TRACE ==
[]
0000 OP_CONSTANT  (00) '3.000000'
[ 3.000000 ]
0002 OP_CONSTANT  (01) '4.000000'
...SNIP...
0598 OP_CONSTANT  (101) '102.000000'
[ 3.000000 ] [ 4.000000 ] [ 0.047935 ] [ 1.000000 ] [ 10100.000000 ] [ 102.000000 ]
0600 OP_MULTIPLY
[ 3.000000 ] [ 4.000000 ] [ 0.047935 ] [ 1.000000 ] [ 1030200.000000 ]
0601 OP_DIVIDE
[ 3.000000 ] [ 4.000000 ] [ 0.047935 ] [ 0.000001 ]
[ 3.000000 ] [ 4.000000 ] [ 0.047936 ]
0603 OP_MULTIPLY
[ 3.000000 ] [ 0.191743 ]
[ 3.191743 ]
0605 OP_RETURN
3.191743

We just executed 605 virtual machine instructions to compute pi to 1dp!

This brings us to the end of this tutorial. To recap we've walked through the whole compilation process: from the user providing an expression string on the REPL, scanning the source string into tokens, parsing the tokens while accounting for relative precedence via a Pratt parser, generating bytecode, and finally executing the bytecode on our own VM. RPython translated what we wrote into C and compiled it, meaning our resulting calc REPL is really fast.

“The world is a thing of utter inordinate complexity and richness and strangeness that is absolutely awesome.”